Create custom button to open the Slideout Filter
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The support doesn work on Saturdays and Sundays, so some Friday requests can be answered on Monday.
Hey, I want use a custom button to open the side out filter but it is not working. This is what I tried so far:
// Get the button element
const span= document.querySelector(".open-the-filter");
// Get the target element
const target = document.querySelector("body > div.woof-slide-out-div.woof_slideout_default.ui-slideouttab-panel.ui-slideouttab-left.ui-slideouttab-ready");
// Add a click event listener to the button
span.addEventListener("click", () => {
// Add the class to the target element
target.classList.add("ui-slideouttab-open");
})How can I make a custom button to open the Slideout?
Hello
I think yes, this is a third party library, please, read docs - https://github.com/microneer/jquery.tabSlideOut.js/blob/master/README.md
here is an example with buttons - http://jsfiddle.net/6kvus71q/27/
Hey Pablo, Can you show me how to implement this into your plugin, please?
Why I cant use the code provided? I just want to open the slideout on click.
Hello
I don't know why your custom code is not working. Unfortunately, customization or fixing custom code is not included in support.
I advise you to read the JS library documentation (what we use for this functionality). The link has code examples for implementing a custom button.